CH4 + | 3 CuO | ---> | 3 Cu + | 2 H2O + | CO | |
basic | 1 molecule | 3 units | ---> | 3 atoms | 2 molecules | 1 molecule |
x2 | 2 molecules | 6 units | ---> | 6 atoms | 4 molecules | 2 molecules |
x12 | 12 molecules | 36 units | ---> | 36 atoms | 24 molecules | 12 molecules |
1 dozen | 3 dozen | ---> | 3 dozen | 2 dozen | 1 dozen | |
x6.02e+23 | 6.02e+23 | 1.81e+24 | ---> | 1.81e+24 | 1.20e+24 | 6.02e+23 |
1 mole | 3 moles | ---> | 3 moles | 2 moles | 1 mole |
First think about what the chemical equation states. The question asks about the relationship between aluminum oxide and aluminum. We can see from the reaction that if 4 moles of Al are used then 2 moles of Al2O3 will be produced. This ratio is fixed, so if we start with 5.40 moles of Al instead, how do we predict the amount of Al2O3 produced?
5.40 | x | |||
4 Al | + | 3 O2 | ---> | 2 Al2O3 |